First, let’s state this: In Om there are no beaming rules per se. Beaming is a result of groups, groups being RT inside RT.
For instance, starting from a simple division of a measure:
we have no beams because the tree is just made of subdivisions. Here we have a tree including another tree of the same proportions, and therefore we get beaming because we have created a group:
Now, concerning omquantify. The quantification depends on the denominator of the time signature. So unfortunately, if you quantify using a 1/4 denominator, your quantification will have as a reference the quarter note. So in the case you have a half beat, you will get a tie, that’s what you are having. It is the internal structure of the rhythm trees. You can check this using mktree like this:
Now in the case you are writing in 3/4, you may get this depending on the RT structure. In the first case you have a group, and therefore beaming (here it is invisible, but you may notice the straight stems), while in the second case, there is no beaming:
In your case here, (and specifically here only), you can bypass this with:
zagny - methods of transformation-1.omp (14.2 KB)
Of course considering you are always using simple proportion. No irrationals allowed or missing beats in the measure.
Hope this helps.
PS: a paper on RTs here: https://www.researchgate.net/publication/4001313_Representation_and_Rendering_of_Rhythmic_Structures